## Is twice as old as her youngest brother if the difference between their ages is 15 years How old is her youngest brother?

If the difference between their ages is 15 years, how old is her youngest brother? b= 15 And Sarah, the problem says, is twice as old: 15*2= 30 Sarah is 30.

## What is four times as old as her brother?

Explanation: When Mary is 16 , her brother is 4 . Let x be the year when Mary will be twice as old as her brother.

## How do you solve age problems in a linear equation?

0:337:14Age word problems 1 | Linear equations | Algebra I | Khan AcademyYouTube

## How do you respond to age problems?

2:4935:19Age Word Problems In Algebra - Past, Present, Future - YouTubeYouTube

## What is Johns present age if after 10 years?

Correct option is 4 We are given that Johns age after 10 years (x + 10) is 5 times his age 5 years ago (x-6).

## When I am as old as my father now I will be five times as old as my son is now but at that time my son will be eight years older than I am now at present the sum of the ages of my father and me is 100 How old is my?

From the statement When I am as old as my father is now, I shall be five times as old as my son is now. we can say: (m + d) = 5s = f: or :d = 5s – m : By then, my son will be eight years older than I am now.

## How do you solve father Son age problems?

The age of the father six years ago = (60 – x) – 6 years = 54 – x years. Hence, we have x = 14 years. Thus the sons age after 6 years = (x+ 6) = (14 + 6) = 20 years. Hence the correct option is C) 20 years.

## What are the main problems of old age?

According to the National Council on Aging, about 92 percent of seniors have at least one chronic disease and 77 percent have at least two. Heart disease, stroke, cancer, and diabetes are among the most common and costly chronic health conditions causing two-thirds of deaths each year.

## What is Krishnas present age if after 10 years his age will be 3 times of present age?

After 10 years his age will be x+10. Hence, Krishnas present age will be 5 years.